[JIPMER (Med.) 2001]
A) 5
B) 4
C) 3
D) 2
Correct Answer: B
$ F{{e}^{2+}} $ ion have 4 unpaired electrons $ F{{e}^{2+}}=26-2=24=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{6} $
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