D-And F-Block Elements Ques 23
Question: In which of the following ionic radii of chromium would be smallest
[MP PET 1994]
Options:
A) $ K_2CrO_4 $
B) $ CrO_2 $
C) $ CrCl_3 $
D) $ CrF_2 $
Show Answer
Answer:
Correct Answer: A
Solution:
Oxidation number of $ Cr $ in options a, b, c and d are +6, + 4, + 3, + 3 respectively. In given options a has high oxidation number therefore its radii will be low. Atomic radii decreases with increase in oxidation no.