SATHEE: Chemical Thermodynamics Question 92

Chemical Thermodynamics Question 92

Question: A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If $Δ H$ is the enthalpy change and $Δ E$ is the change in internal energy, then [KCET 2005]

Options:

A) $Δ H > Δ E$

B) $Δ H < Δ E$

C) $Δ H = Δ E$

D) The relationship depends on the capacity of the vessel

Show Answer

Answer:

Correct Answer: B

Solution:

Formation of $C O_{2}$ from $C O$ is an exothermic reaction; heat is evolved from the system, i.e., energy is lowered. Thus, exothermic reactions occur spontaneously on account of decrease in enthapy of system. Thus, $Δ E > Δ H$ .

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Chemical Thermodynamics Question 92

Question: A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If ΔH is the enthalpy change and ΔE is the change in internal energy, then [KCET 2005]

Options:

Answer:

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Question: A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If $Δ H$ is the enthalpy change and $Δ E$ is the change in internal energy, then [KCET 2005]