Chemical Thermodynamics Question 489
Question: If heat of dissociation of $ CHCl_2COOH $ is 0.7 kcal/mol, then $ \Delta H $ for the reaction: $ CHCl_2COOH+KOH\to CHCl_2COOK+H_2O $
Options:
A) - 13 kcal
B) + 13 kcal
C) - 14.4 kcal
D) - 13.7 kcal
Show Answer
Answer:
Correct Answer: A
Solution:
- $ {{H}^{+}}+O{{H}^{-}}\to H_2{O_{(l)}} $
$ \Delta H=-13.7kcal $ …(i) $ CHCl_2COOH\to CHCl_2CO{{O}^{-}}+{{H}^{+}} $
$ \Delta H=0.7,kcal $ ….(ii) $ CHCl_2COOH+O{{H}^{-}}\to CHCl_2CO{{O}^{-}}+H_2{O_{(l)}} $
$ \Delta H=- $
Adding Eq. (i) and (ii), $ \Delta H $ = - 13 kcal.
