Chemical Thermodynamics Question 488

Question: The in ΔfH(N2O5,g) kJ/mol on the basis of the following data is -

2NO(g)+O2(g)2NO2(g);

ΔrH=114,kJ/mol

4NO2(g)+O2(g)2N2O5(g);

ΔrH=102.6,kJ/mol

ΔfH(NO,g)=90.2kJ/mol

Options:

A) 15.1

B) 30.2

C) - 36.2

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

  • 12N2(g)+12O2(g)NO(g);ΔfHo=90.2

N2(g)+O2(g)2NO(g);ΔfHo=90.2×2 …(1) 2NO(g)+O2(g)2NO2(g);ΔfHo=114 …(2) 2NO2(g)+12O2(g)N2O5(g);

ΔHo=102.62=51.3 …(3) Eq.(1)+(2)+(3)

N2(g)+52O2(g)N2O5(g)

ΔfHo(N2O5,g)=15.1kJ/mol



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