Chemical Thermodynamics Question 460

Question: One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of $ 27^{o}C $ . If the work done during the process is 3 kJ, the final temperature will be equal to $ (C_{v}=20,J{{K}^{-1}}) $

Options:

A) 150 K

B) 100 K

C) $ {{26.85}^{o}}C $

D) 295 K

Show Answer

Answer:

Correct Answer: A

Solution:

  • We know that work done, $ W=C_{v}(T_1-T_2) $

$ 3\times 1000=20,(300-T_2) $ ;
$ \therefore 3000=6000-20,T_2 $

$ \therefore T_2=\frac{3000}{20}=150,K $ .



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