Chemical Thermodynamics Question 42

Question: The entropy changed involved in the conversion of 1 mole of liquid water at 373 K to vapour at the same temperature will be [ΔHvap=2.257kJ/gm] [MP PET 2002]

Options:

A) 0.119 kJ

B) 0.109 kJ

C) 0.129 kJ

D) 0.120 kJ

Show Answer

Answer:

Correct Answer: B

Solution:

H2O(l)H2O(g),,ΔS=ΔHvapT,

ΔHvap.=2.257,KJ/g or ΔHvap=2.257×18,kJ/mol.,=40.7,KJ/mol

hence, ΔS=40.7373=0.109,kJ/mol/K.



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