Chemical Thermodynamics Question 403

Question: What is the equilibrium constant if ATP hydrolysis by water produce standard free energy of $ -50kJ/mol $ under normal body conditions-

Options:

A) $ 2.66\times 10^{8} $

B) $ 5.81\times 10^{8} $

C) $ 1.18\times 10^{7} $

D) $ 1.98\times 10^{8} $

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ \Delta G=-RT $ ln $ K_{eq} $ : Normal body temperature $ =37{}^\circ C $

$ \Rightarrow -50\frac{KJ}{mol}=8.314\frac{J}{Kmol}\times 310,\ln K_{eq} $

$ \Rightarrow 19.39=\ln K_{eq} $

$ \Rightarrow K_{eq}=2.6\times 10^{8} $



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