Chemical Thermodynamics Question 379
Question: The entropy of a sample of a certain substance increases by $ 0.836J{{K}^{-1}} $ on adding reversibly 0.3344 J of heat at constant temperature. The temperature of the sample is:
Options:
A) $ 2.5K $
B) $ 0.3K $
C) $ 0.016K $
D) $ ~0.4K $
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Answer:
Correct Answer: D
Solution:
- $ \Delta S=\frac{\Delta H}{T};\text{ T}=\frac{\Delta H}{\Delta S}=\frac{0.3344}{0.836}=0.4K $