Chemical Thermodynamics Question 379

Question: The entropy of a sample of a certain substance increases by $ 0.836J{{K}^{-1}} $ on adding reversibly 0.3344 J of heat at constant temperature. The temperature of the sample is:

Options:

A) $ 2.5K $

B) $ 0.3K $

C) $ 0.016K $

D) $ ~0.4K $

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Answer:

Correct Answer: D

Solution:

  • $ \Delta S=\frac{\Delta H}{T};\text{ T}=\frac{\Delta H}{\Delta S}=\frac{0.3344}{0.836}=0.4K $


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