SATHEE: Chemical Thermodynamics Question 35

Chemical Thermodynamics Question 35

Question: The volume of a gas decreases from $500, c c$ to $300, c c$ when a sample of gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is [Pb. PMT 2000]

Options:

A) - 2.16 J

B) 12.156 J

C) 2.16 J

D) 101.3 J

Show Answer

Answer:

Correct Answer: C

Solution:

Here: Change in Volume $(V) = 500 - 300 = 200 c c = 0.2, l i t r e,$

Pressure $(P) = 0.6, a t m$ and heat liberated (q) = 10J Work done $(W) = P Δ V = (0.2 \times 0.6) = 0.12, l i t r e - a t m$

But $1, l i t r e - a t m = 101.3, J$ . hence $W = 0.12 \times 101.3 = 12.156, J$ .

We also know that heat is liberated, therefore it would be negative. Thus change in $Δ E = q + W = - 10 + 12.16 = 2.16, J$ .

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Chemical Thermodynamics Question 35

Question: The volume of a gas decreases from 500,cc to 300,cc when a sample of gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is [Pb. PMT 2000]

Options:

Answer:

Solution:

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Question: The volume of a gas decreases from $500, c c$ to $300, c c$ when a sample of gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is [Pb. PMT 2000]