Chemical Thermodynamics Question 340

Question: The latent heat of vapourization of $ \varepsilon $ liquid at 500 K and 1 atm pressure is 10.0 kcal/mol. What will be the change in internal energy $ ( \Delta U ) $ of 3 moles of liquid at the same temperature

Options:

A) $ 13.0kcal/mol $

B) $ -13.0kcal/mol $

C) $ 27.0kcal $

D) $ -7.0kcal/mol $

Show Answer

Answer:

Correct Answer: C

Solution:

$ 3H_2O(l)\to 3H_2O(g); $

$ \Delta n=3,\Delta E=\Delta H-\Delta nRT $

$ =30-3\times \frac{2}{1000}\times 500=27kcal $



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