Chemical Thermodynamics Question 31

Question: An engine operating between $ 150^{o}C $ and $ 25^{o}C $ takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is [MH CET 1999]

Options:

A) 147.7 J

B) 157.75 J

C) 165.85 J

D) 169.95 J

Show Answer

Answer:

Correct Answer: A

Solution:

$ T_2=150+273=423,K $

$ T_1=25+273=298,K $

$ Q=500,K $

$ \frac{W}{Q}=\frac{T_2-T_1}{T_2} $ ; $ W=500( \frac{423-298}{423} )=147.7,J $ .



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