Chemical Thermodynamics Question 31
Question: An engine operating between $ 150^{o}C $ and $ 25^{o}C $ takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is [MH CET 1999]
Options:
A) 147.7 J
B) 157.75 J
C) 165.85 J
D) 169.95 J
Show Answer
Answer:
Correct Answer: A
Solution:
$ T_2=150+273=423,K $
$ T_1=25+273=298,K $
$ Q=500,K $
$ \frac{W}{Q}=\frac{T_2-T_1}{T_2} $ ; $ W=500( \frac{423-298}{423} )=147.7,J $ .
