Chemical Thermodynamics Question 278
Question: The heat of neutralization of $ HCl $ and $ NaOH $ is [MP PET 2001]
Options:
A) Zero
B) - 57.3 kJ
C) + 57.3 kJ
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Strong acid $ (HCl) $ and strong base $ (NaOH) $ shows $ \Delta {H_{neutralization}} $ = -57.3 kJ.