Chemical Thermodynamics Question 270

Question: The heat evolved in the combustion of benzene is given by the equation $ C_6H_6(l)+7\frac{1}{2}O_2(g)\to 3H_2O(l)+6CO_2(g) $

$ \Delta H=781.0,kcalmo{{l}^{-1}} $ Which of the following quantities of heat energy will be evolved when 39 g of benzene is burnt in an open container [MP PET 2000]

Options:

A) 122.25 kcal $ mo{{l}^{-1}} $

B) 390.5 kcal $ mo{{l}^{-1}} $

C) 1562.0 kcal $ mo{{l}^{-1}} $

D) 586.75 kcal $ mo{{l}^{-1}} $

Show Answer

Answer:

Correct Answer: B

Solution:

Heat evolved during burning of $ 39g $

$ C_6H_6=\frac{781.0\times 39}{78}=390.5,kcal,mo{{l}^{-1}} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक