Chemical Thermodynamics Question 178
Question: Given that $ 2C(s)+2O_2(g)\to 2CO_2(g);\Delta H=-787,kJ $
$ H_2(g)+\frac{1}{2}O_2(g)\to H_2O(l);\Delta H=-286,kJ $
$ C_2H_2(g)+2\frac{1}{2}O_2(g)\to 2CO_2(g)+H_2O(l);,\Delta H=-1301,kJ $ Heat of formation of acetylene is [KCET 1989; Orissa JEE 2005]
Options:
A) $ -,1802,kJ $
B) $ +,1802,kJ $
C) $ -800,kJ $
D) $ +228,kJ $
Show Answer
Answer:
Correct Answer: D
Solution:
Aim: $ 2C+{H_{2(g)}}\to C_2{H_{2(g)}} $ . eq. (ii) + eq. (iii) - eq. (iv) - eq. (i) find the required result.
