Chemical Thermodynamics Question 155
Question: The equilibrium concentration of the species in the reaction $ A+B\equiv C+D $ are 3, 5, 10 and 15 $ mole,{{L}^{-1}} $ respectively at $ 300,K $ the $ \Delta G $ for the reaction is [Pb. PMT 2004]
Options:
A) 13.81
B) - 1381.8
C) - 138.18
D) 1391.6
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta G=-2.303,RT,\log ,{K}’ $ , Here $ R=2,cal,T=300K $
$ {K}’=\frac{10\times 15}{3\times 5}=10 $ ; $ \Delta G=-2.303\times 2\times 300\times {\log_{10}}10 $
$ =-2.303\times 2\times 300\times 1=-1381.8,cal $
