Chemical Thermodynamics Question 112
Question: Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is (Gas constant = 2) [AIIMS 2000]
Options:
A) 938.8 cal.
B) 1138.8 cal.
C) 1381.8 cal.
D) 1581.8 cal.
Show Answer
Answer:
Correct Answer: C
Solution:
$ -,W=+,2.303,nRT, $ log $ \frac{p_1}{p_2} $
$ -,W=2.303\times 1\times 2\times 300 $ log $ \frac{10}{1} $
$ =1381.8,cal. $
