SATHEE: Chemical Kinetics Question 86

Chemical Kinetics Question 86

Question: A reaction that is of the first order with respect to reactant A has a rate constant $6 {min}^{- 1} .$ If we start with $[A] = 0.5, m o l l^{- 1}$ , when would $[A]$ reach the value 0.05mol $l^{- 1}$ [KCET 2000]

Options:

A) 0.384 min

B) 0.15 min

C) 3 min

D) 3.84 min

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Answer:

Correct Answer: A

Solution:

We know that for first order kinetics

$k = \frac{2.303}{t} \log \frac{a}{a - x}$

$(a - x) = 0.05 m o l l^{- 1}$ , $6 = \frac{2.303}{t} \log \frac{0.5}{0.05}$ or $t = \frac{2.303}{6} \log \frac{0.5}{0.05} = \frac{2.303}{6} = 0.384, min$

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Chemical Kinetics Question 86

Question: A reaction that is of the first order with respect to reactant A has a rate constant $6 {min}^{- 1} .$ If we start with $[A] = 0.5, m o l l^{- 1}$ , when would $[A]$ reach the value 0.05mol $l^{- 1}$ [KCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Chemical Kinetics Question 86

Question: A reaction that is of the first order with respect to reactant A has a rate constant 6min−1. If we start with [A]=0.5,moll−1 , when would [A] reach the value 0.05mol l−1 [KCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A reaction that is of the first order with respect to reactant A has a rate constant $6 {min}^{- 1} .$ If we start with $[A] = 0.5, m o l l^{- 1}$ , when would $[A]$ reach the value 0.05mol $l^{- 1}$ [KCET 2000]