Chemical Kinetics Question 70
Question: In the reaction $ 2N_2O_5\to 4NO_2+O_2 $ , initial pressure is $ 500,atm $ and rate constant $ K $ is $ 3.38\times {10^{-5}}{{\sec }^{-1}} $ . After 10 minutes the final pressure of $ N_2O_5 $ is [Orissa JEE 2005]
Options:
A) 490 atm
B) 250 atm
C) 480 atm
D) 420 atm
Show Answer
Answer:
Correct Answer: A
Solution:
$ p_0=500,atm $
$ K=\frac{2.303}{t}{\log_{10}}\frac{p_0}{p_{t}} $
$ 3.38\times {10^{-5}}=\frac{2.303}{10\times 60}\log \frac{500}{p_{t}} $ or $ 0.00880=\log \frac{500}{p_{t}}\Rightarrow \frac{500}{1.02}=490,atm $
