Chemical Kinetics Question 31

Question: If we plot a graph between log K and $ \frac{1}{T} $ by Arrhenius equation, the slope is [UPSEAT 2001]

Options:

A) $ -\frac{E_{a}}{R} $

B) $ +\frac{E_{a}}{R} $

C) $ -\frac{E_{a}}{2.303,R} $

D) $ +\frac{E_{a}}{2.303,R} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \ln K=\ln $

$ -\frac{E_{a}}{RT} $ is Arrhenius equation. Thus plots of ln K vs 1/T will give slope $ =-E_{a}/RT $ or $ -E_{a}/2.303R $ .



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