Chemical Kinetics Question 301
Question: The time taken for 90% of a first order reaction to complete is approximately
Options:
A) 1.1 times that of half-life
B) 2.2 times that of half-life
C) 3.3 times that of half-life
D) 4.4 times that of half-life
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ t_{90} $ % $ =\frac{2.303}{k}\log \frac{100}{100-50}(I) $
$ t_{50} $ % $ =\frac{2.303}{k}\log \frac{100}{100-50}(II) $
$ \therefore t_{90} $ % $ =3.3,t_{50} $ %
