SATHEE: Chemical Kinetics Question 30

Chemical Kinetics Question 30

Question: The rate law for a reaction between the substances A and B is given by, rate $= k {[A]}^{n} {[B]}^{m}$ . On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as [AIEEE 2003]

Options:

A) $\frac{1}{2^{(m + n)}}$

B) $(m + n)$

C) $(n - m)$

D) $2^{(n - m)}$

Show Answer

Answer:

Correct Answer: D

Solution:

$R = K {(A)}^{n} {(B)}^{m}$

$R^{'} = K {(2 A)}^{n} {(\frac{B}{2})}^{m}$

$= K {(A)}^{n} 2^{n} {(B)}^{m} 2^{- m}$

$= K {(A)}^{n} {(B)}^{m} 2^{n - m}$ , $\frac{R^{'}}{R} = \frac{K {(A)}^{n} {(B)}^{m} 2^{n - m}}{K {(A)}^{n} {(B)}^{m}} = 2^{n - m}$

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Chemical Kinetics Question 30

Question: The rate law for a reaction between the substances A and B is given by, rate =k[A]n[B]m . On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as [AIEEE 2003]

Options:

Answer:

Solution:

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Question: The rate law for a reaction between the substances A and B is given by, rate $= k {[A]}^{n} {[B]}^{m}$ . On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as [AIEEE 2003]