SATHEE: Chemical Kinetics Question 297

Chemical Kinetics Question 297

Question: In the reaction, $A + 2 B \overset{}{\to} 6 C + 2 D$ , If the initial rate $- \frac{d [A]}{d t}$ at t = 0 is $2.6 \times 10^{- 2} M s e c^{- 1}$ what will be the value of $\frac{d [B]}{d t}$ at $t = 0$ -

Options:

A) $8.5 \times 10^{- 2} M s e c^{- 1}$

B) $2.5 \times 10^{- 2} M s e c^{- 1}$

C) $5.2 \times 10^{- 2} M s e c^{- 1}$

D) $7.5 \times 10^{- 2} M s e c^{- 1}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Rate of reaction $= \frac{R a t e o f d i s a p p e a r a n c e / a p p e a r a n c e}{S t o i c h i o m e t r i c c o e f f i c i e n t}$

$= - \frac{d [A]}{d t} = \frac{1}{2} \frac{d [B]}{d t} = 2.6 \times 10^{- 2}$

$= - \frac{1}{2} \frac{d [B]}{d t}$

$5.2 \times 10^{- 2} = - \frac{d [B]}{d t}$

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Chemical Kinetics Question 297

Question: In the reaction, A+2B→6C+2D , If the initial rate −d[A]dt at t = 0 is 2.6×10−2Msec−1 what will be the value of d[B]dt at t=0 -

Options:

Answer:

Solution:

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Question: In the reaction, $A + 2 B \overset{}{\to} 6 C + 2 D$ , If the initial rate $- \frac{d [A]}{d t}$ at t = 0 is $2.6 \times 10^{- 2} M s e c^{- 1}$ what will be the value of $\frac{d [B]}{d t}$ at $t = 0$ -