Chemical Kinetics Question 291
Question: For the reaction, $ 2N_2O_5\to 4NO_2+O_2 $ the rate equation can be expressed in two ways $ -\frac{d[N_2O_5]}{dt}=k[N_2O_5] $ and $ +\frac{d[NO_2]}{dt}=k’[N_2O_5] $ k and k’ are related as:
Options:
A) $ k=k’ $
B) $ 2k=k’ $
C) $ k=2k’ $
D) $ k=4k’ $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Rate of disappearance of reactant= Rate of appearance of products $ -\frac{1}{2}\frac{d[N_2O_5]}{dt}=\frac{1}{4}\frac{d[NO_2]}{dt} $
$ \frac{1}{2}k[N_2O_5]=\frac{1}{4}k’[N_2O_5] $
$ \frac{k}{2}=\frac{k’}{4} $
$ \therefore k’=2k $
