Chemical Kinetics Question 289
Question: $ A+2B\to C $ , the rate equation for this reaction is given as Rate $ =K[ A ][ B ]. $ If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself-
Options:
A) halved
B) the same
C) doubled
D) quadrupled
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ Rate=k[ A ][ B ]=R $
$ R’=k[ A ][ 2B ] $
$ \frac{R}{R’}=\frac{k[A][B]}{k[A][2B]}=\frac{k[A][B]}{2k[A][B]} $
$ \Rightarrow 2R=R’ $ i.e., rate become doubles.
