Chemical Kinetics Question 289

Question: A+2BC , the rate equation for this reaction is given as Rate =K[A][B]. If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself-

Options:

A) halved

B) the same

C) doubled

D) quadrupled

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Rate=k[A][B]=R

R=k[A][2B]

RR=k[A][B]k[A][2B]=k[A][B]2k[A][B]
2R=R i.e., rate become doubles.



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