Chemical Kinetics Question 264

Question: The rate law for a reaction between the substances A and B is given by rate =k[A]n[B]m On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

Options:

A) (m+n)

B) (nm)

C) 2(n+m)

D) 12(m+n)

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Rate1=k[A]n[B]m;Rate2=k[2A]n[1/2B]m
Rate2Rate1=k[2A]n[1/2B]mk[A]n[B]m

=[2]n[1/2]m=2n.,2m=2nm



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