Chemical Kinetics Question 254

Question: The velocity constant of a reaction at 290 K was found to be $ 3.2\times {10^{-3}} $ . At 300 K it will be [MP PMT 2004]

Options:

A) $ 1.28\times {10^{-2}} $

B) $ 6.4\times {10^{-3}} $

C) $ 9.6\times {10^{-3}} $

D) $ 3.2\times {10^{-4}} $

Show Answer

Answer:

Correct Answer: B

Solution:

As we know that the velocity constant become double by increasing the temperature by 10°C so if at 290 K, velocity constant $ =3.2\times {10^{-3}} $ then at 300 K, velocity constant $ =2(K_{290}) $

$ =2\times 3.2\times {10^{-3}} $

$ =6.4\times {10^{-3}} $ .



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