Chemical Kinetics Question 210
Question: The half-life of 2 sample are 0.1 and 0.4 seconds. Their respective concentration are 200 and 50 respectively. What is the order of the reaction [JEE Orissa 2004]
Options:
A) 0
B) 2
C) 1
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
$ {t_{1/2}}\propto {a^{1-n}} $
Þ $ \frac{0.1}{0.4}=\frac{{{(200)}^{1-n}}}{{{(50)}^{1-n}}} $
Þ $ \frac{1}{4}={{[ \frac{4}{1} ]}^{1-n}}={{[ \frac{1}{4} ]}^{n-1}} $
Þ $ \frac{1}{4^{1}}=\frac{1}{{4^{n-1}}} $
$ \therefore \ \ n-1=1 $ ; $ n=2 $ .
