Chemical Kinetics Question 196
Question: The reaction $ A\to B $ follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B [CBSE PMT 2003]
Options:
A) 2 hours
B) 1 hour
C) 0.5 hour
D) 0.25 hour
Show Answer
Answer:
Correct Answer: B
Solution:
$ k=\frac{2.303}{t}\log \frac{0.8}{0.6}=2.303\log \frac{4}{3} $
$ t=\frac{2.303}{k}\log \frac{0.9}{0.675}=\frac{2.303}{k}\log \frac{4}{3} $ ; $ t=1 $ hour.
