Chemical Kinetics Question 174

Question: The rate constant for a second order reaction is $ 8\times {10^{-5}}{M^{-1}}mi{n^{-1}} $ . How long will it take a 1M solution to be reduced to 0.5 M [MH CET 2001]

Options:

A) $ 8\times {10^{-5}} $ min

B) $ 8.665\times 10^{3} $ min

C) $ 4\times {10^{-5}} $ min

D) $ 1.25\times 10^{4} $ min

Show Answer

Answer:

Correct Answer: D

Solution:

$ 8\times {10^{-5}}=\frac{1}{t}[ \frac{1}{0.5}-\frac{1}{1} ] $ ; $ 8\times {10^{-5}}=\frac{1}{t}[2-1] $

$ t=\frac{1}{8\times {10^{-5}}}=0.125\times 10^{5}=1.25\times 10^{4}min. $



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