A) K
B) $ \frac{1.303,\log ,2}{K} $
C) $ \frac{2.303,\log ,2}{K} $
D) $ \frac{9}{K} $
Correct Answer: C
$ {t_{1/2}}=\frac{2.303\log 2}{K}=\frac{0.693}{K} $
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