Chemical Kinetics Question 116

Question: The half life period of a first order reaction [AMU 2000]

Options:

A) $ \frac{0.693}{t} $

B) $ \frac{0.693}{K} $

C) $ \frac{2.303}{t} $

D) $ \frac{0.303}{K_1} $

Show Answer

Answer:

Correct Answer: B

Solution:

Derive $ {t_{1/2}} $ from $ K_{t}=2.303\log \frac{a}{a-x} $ , putting $ t=\frac{1}{2} $ and $ x=\frac{a}{2} $ . Therefore it is $ \frac{0.693}{K} $ .



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