Chemical Kinetics Question 116
Question: The half life period of a first order reaction [AMU 2000]
Options:
A) $ \frac{0.693}{t} $
B) $ \frac{0.693}{K} $
C) $ \frac{2.303}{t} $
D) $ \frac{0.303}{K_1} $
Show Answer
Answer:
Correct Answer: B
Solution:
Derive $ {t_{1/2}} $ from $ K_{t}=2.303\log \frac{a}{a-x} $ , putting $ t=\frac{1}{2} $ and $ x=\frac{a}{2} $ . Therefore it is $ \frac{0.693}{K} $ .
