SATHEE: Chemical Bonding And Molecular Structure Question 94

Chemical Bonding And Molecular Structure Question 94

Question: The dipole moment of HBr is $1.6 \times 10^{- 30}$ cm and interatomic spacing is 1Å. The % ionic character of HBr is

Options:

A) 7

B) 10

C) 15

D) 27

Show Answer

Answer:

Correct Answer: B

Solution:

Charge of $e^{-} = 1.6 \times 10^{- 19}$ Dipole moment of $H B r = 1.6 \times 10^{- 30}$ Inter atomic spacing $= 1 \AA = 1 \times 10^{- 10} m$ % of ionic character in $H B r = \frac{d i p o l e, m o m e n t, o f, H B r \times 100}{i n t e r, s p a c i n g, d i s t a n c e, \times q}$

$= \frac{1.6 \times 10^{- 30}}{1.6 \times 10^{- 19} \times 10^{- 10}} \times 100$

$= 10^{- 30} \times 10^{29} \times 100 = 10^{- 1} \times 100$

$= 0.1 \times 100 = 10$

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Chemical Bonding And Molecular Structure Question 94

Question: The dipole moment of HBr is 1.6×10−30 cm and interatomic spacing is 1Å. The % ionic character of HBr is

Options:

Answer:

Solution:

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Question: The dipole moment of HBr is $1.6 \times 10^{- 30}$ cm and interatomic spacing is 1Å. The % ionic character of HBr is