Chemical Bonding And Molecular Structure Question 61
Question: The structure of orthophosphoric acid is [KCET 2003]
Options:
A) $ H-O-\overset{,O,}{\mathop{\underset{H}{\mathop{\underset{|,}{\mathop{\underset{,O,}{\mathop{\underset{|,}{\overset{\uparrow ,}{\mathop{P}}},}},}},}},}},-O-H $
B) $ O\rightarrow \underset{,H,}{\mathop{\underset{|,}{\mathop{\underset{,O,}{\overset{,H,}{\mathop{\underset{|,}{\overset{|}{\mathop{P}}},}}},}},}},-O-H $
C) $ O\rightarrow \underset{H,}{\overset{H}{\mathop{\underset{|,}{\overset{|}{\mathop{P,}}},}}},-O-H $
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D) $ H-O-\overset{,O}{\mathop{\overset{\uparrow }{\mathop{P}},}},=O $
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Show Answer
Answer:
Correct Answer: A
Solution:
$ H_3PO_4 $ is orthophosphoric acid. $ H-O-\underset{\underset{\underset{H}{\mathop{|}},}{\mathop{O}},}{\overset{O}{\mathop{\underset{|}{\overset{\uparrow }{\mathop{P}}},}}},-O-H $
