Chemical Bonding And Molecular Structure Question 441
Question: In the reaction $ 2PCl_5\rightarrow PCl_4^{-}+PCl_6^{-} $ , the change in hybridization is from
Options:
A) $ sp^{3}d $ to $ sp^{3} $ and $ sp^{3}d^{2} $
B) $ sp^{3}d $ to $ ~sp^{2} $ and $ sp^{3} $
C) $ sp^{3}d $ to $ sp^{3}d^{2} $ and $ sp^{3}d^{3} $
D) $ sp^{3}d^{2} $ to $ sp^{3} $ and $ sp^{3}d $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \begin{matrix} 2PCl_5\rightarrow PCl_4^{+}+PCl_6^{-} & {} \\ \end{matrix} \\ \begin{matrix} \uparrow ,sp^{3}d & \uparrow ,sp^{3} & \uparrow ,sp^{3}d^{2} \\ \end{matrix} $
