Chemical Bonding And Molecular Structure Question 424
Question: The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and $ 2.67\overset{o}{\mathop{A}}, $ , respectively. This indicates that
Options:
A) bonding is 100% ionic in both the molecules
B) AB has more ionic bond character than CD
C) AB has lesser ionic bond character than CD
D) bonding is nearly covalent in both the molecules
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Answer:
Correct Answer: C
Solution:
- As dipole moment = electric charge $ \times $ bond length
D. M. of AB molecule $ =4.8\times {10^{-10}}\times 2.82\times {10^{-8}}=13.53D $
D.M. of CD molecule $ =4.8\times {10^{-10}}\times 2.67\times {10^{-8}}=12.81D $
Now % ionic character $ =\frac{Actualdipolemomentofthebond}{Dipolemomentofpureioniccompound}\times 100 $ then % ionic character in AB
$ =\frac{10.41}{13.53}\times 100=76.94 $ %
% ionic character in CD $ =\frac{10.27}{12.81}\times 100=80.17 $ %
