Chemical Bonding And Molecular Structure Question 361
Question: According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $ O_2^{+} $
Options:
A) Paramagnetic and bond order< $ O_2 $
B) Paramagnetic and bond order> $ O_2 $
C) Dimagnetic and bond order< $ O_2 $
D) Dimagnetic and bond order> $ O_2 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ O_2 $ : $ \sigma 1s^{2},{{\sigma }^{*}}1s^{2},\sigma 2s^{2},{{\sigma }^{*}}2s^{2},\sigma 2p_x^{2} \begin{matrix} \pi 2p_y^{2} \\ {} \\ \pi 2p_z^{2} \\ \end{matrix} .\ \begin{matrix} {{\pi }^{*}}2p_y^{1} \\ {} \\ {{\pi }^{*}}2p_z^{1} \\ \end{matrix} . $
Bond order $ =\frac{10-6}{2}=2.0 $ (Two unpaired electrons in antibonding molecular orbital) $ O_2^{+}:\sigma 1s^{2},{{\sigma }^{*}}1s^{2},\sigma 2s^{2},{{\sigma }^{*}}2s^{2},\sigma 2p_x^{2} \begin{matrix} \pi 2py^{2} \\ \pi 2pz^{2} \\ \end{matrix} . \begin{matrix} {{\pi }^{*}}2py^{1} \\ {{\pi }^{*}}2pz^{0} \\ \end{matrix} . $
Bond order $ =\frac{10-5}{2}=2.5 $ (One unpaired electron in antibonding molecular orbital so it is paramagnetic)
