Chemical Bonding And Molecular Structure Question 357
Question: The bond order of $ O_2^{+} $ is the same as in [CPMT 2004]
Options:
A) $ N_2^{+} $
B) $ C{N^{-}} $
C) $ CO $
D) $ N{O^{+}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ O_2^{+}(15{e^{-}})=K:{K^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2p_{x})}^{2}} $
$ {{(\pi 2p_{y})}^{2}}{{(\pi 2p_{z})}^{2}}{{({{\pi }^{*}}2p_{y})}^{1}}{{({{\pi }^{*}}2p_{z})}^{0}} $
Hence, bond order $ =\frac{1}{2}(10-5)=2.5 $
$ N_2^{+}(13{e^{-}})=K{K^{*}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2p_{x})}^{2}} $
$ {{(\pi ,2p_{y})}^{2}}{{(\pi ,2p_{z})}^{1}} $
Hence, bond order $ =\frac{1}{2}(9-4)=2.5 $ .
