Chemical Bonding And Molecular Structure Question 123
Question: Chloride of metal is $ MCl_2 $ . The formula of its phosphate will be [CPMT 1979]
Options:
A) $ M_2PO_4 $
B) $ M_3{{( PO_4 )}_2} $
C) $ M_2{{( PO_4 )}_3} $
D) $ MPO_4 $
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Answer:
Correct Answer: B
Solution:
Since the chloride of a metal is $ MCl_2 $ therefore metal -M- must be divalent i.e. $ {M^{2+}} $ . As a result the formula of its phosphate is $ M_3{{(PO_4)}_2} $ .