SATHEE: Atomic Structure Question 475

Atomic Structure Question 475

Question: Photon having wavelength 310 nm is used to break the bond of $A_{2}$ molecule having bond energy $288, k g, m o l^{- 1}$ then % of energy of photon converted to the K.E. is

$[h c = 12400, e v, \overset{o}{A},,, 1, e v = 96, k J / m o l]$

Options:

A) 25

B) 50

C) 75

D) 80

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Answer:

Correct Answer: A

Solution:

Energy of on photon $= \frac{12400}{3100} = 4, e V =$

$4 \times 96 = 384 k J, m o l^{- 1}$

$∴$ % of energy converted to $K . E . = \frac{384 - 288}{384} = \frac{96}{384} \times 100 = 25$

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Atomic Structure Question 475

Question: Photon having wavelength 310 nm is used to break the bond of $A_{2}$ molecule having bond energy $288, k g, m o l^{- 1}$ then % of energy of photon converted to the K.E. is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Atomic Structure Question 475

Question: Photon having wavelength 310 nm is used to break the bond of A2 molecule having bond energy 288,kg,mol−1 then % of energy of photon converted to the K.E. is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Photon having wavelength 310 nm is used to break the bond of $A_{2}$ molecule having bond energy $288, k g, m o l^{- 1}$ then % of energy of photon converted to the K.E. is