Atomic Structure Question 435

Question: If the wavelength of the electromagnetic radiation is increased to thrice the digital value, then what will be the percent change in the value of frequency of the electromagnetic radiation.

Options:

A) Increases by 33%

B) Decreases by 33%

C) Increases by 66%

D) Decreases by 66%

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ v_1=\frac{c}{{\lambda_1}} $

$ v_2=\frac{c}{{\lambda_2}}=\frac{c}{3{\lambda_1}} $ % change in frequency $ =\frac{v_2-V_1}{v_1}\times 100 $

$ =\frac{\frac{c}{3{\lambda_1}}-\frac{c}{{\lambda_1}}}{\frac{c}{{\lambda_1}}}\times 100=\frac{-\frac{2c}{3{\lambda_1}}\times 100}{\frac{c}{{\lambda_1}}} $

$ =-66% $ %



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