SATHEE: Atomic Structure Question 402

Atomic Structure Question 402

Question: The $L i^{2 +}$ ion is moving in the third stationary state, and its linear momentum is $7.3 \times 10^{- 34} g m s^{- 1}$ . Angular momentum is.

Options:

A) $1.158 \times 10^{- 45} k g m^{2} s^{- 1}$

B) $1.158 \times 10^{- 48} k g m^{2} s^{- 1}$

C) $1.158 \times 10^{- 47} k g m^{2} s^{- 1}$

D) $12 \times 10^{- 45} k g m^{2} s^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

Z= 3 for $L i^{2 +}$ ions So $r_{n} = \frac{52.9 \times n^{2}}{Z} p m$

$n = 3, Z = 3$

$r_{n} = \frac{52.9 \times {(3)}^{2}}{3} p m$

$= 158.7 p m$ Also, linear momentum (mv) $= 7.3 \times 10^{- 34} k g m s^{- 1}$ Then angular momentum will be $ω = (m v) \times r$

$= (7.3 \times 10^{- 34} k g m s^{- 1}) (158.7 p m)$

$= 7.3 \times 10^{- 34} k g m s^{- 1} \times (158.7 \times 10^{- 12} m)$

$= 11.58 \times 10^{- 48} k g m^{2} s^{- 1}$

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Atomic Structure Question 402

Question: The Li2+ ion is moving in the third stationary state, and its linear momentum is 7.3×10−34gms−1 . Angular momentum is.

Options:

Answer:

Solution:

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Question: The $L i^{2 +}$ ion is moving in the third stationary state, and its linear momentum is $7.3 \times 10^{- 34} g m s^{- 1}$ . Angular momentum is.