Atomic Structure Question 39

Question: The value of the energy for the first excited state of hydrogen atom will be

Options:

A) $ -,13.6,eV $

B) $ -,3.40,eV $

C) $ -,1.51,eV $

D) $ -,0.85,eV $

Show Answer

Answer:

Correct Answer: B

Solution:

$ E=\frac{-13.6}{n^{2}}eV=\frac{-13.6}{2^{2}}=\frac{-13.6}{4}=-3.40eV $



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