Atomic Structure Question 39
Question: The value of the energy for the first excited state of hydrogen atom will be
Options:
A) $ -,13.6,eV $
B) $ -,3.40,eV $
C) $ -,1.51,eV $
D) $ -,0.85,eV $
Show Answer
Answer:
Correct Answer: B
Solution:
$ E=\frac{-13.6}{n^{2}}eV=\frac{-13.6}{2^{2}}=\frac{-13.6}{4}=-3.40eV $