Atomic Structure Question 383

Question: If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom, the total energy of the revolving electron will be:

Options:

A) $ \frac{1}{2}\frac{e^{2}}{r} $

B) $ -\frac{e^{2}}{r} $

C) $ \frac{me^{2}}{r} $

D) $ -\frac{1}{2}\frac{e^{2}}{r} $

Show Answer

Answer:

Correct Answer: D

Solution:

  • Total energy of a revolving electron is the sum of its kinetic and potential energy. Total energy $ =K.E.+P.E. $

$ =\frac{e^{2}}{2r}+( -\frac{e^{2}}{r} )=-\frac{e^{2}}{2r} $



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