Atomic Structure Question 32
Question: Energy of electron of hydrogen atom in second Bohr orbit is
Options:
A) $ -5.44\times {10^{-19}}J $
B) $ -5.44\times {10^{-19}},kJ $
C) $ -5.44\times {10^{-19}},cal $
D) $ -5.44\times {10^{-19}},eV $
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=-\frac{2.172\times {10^{-18}}}{n^{2}}=\frac{-2.172\times {10^{-18}}}{2^{2}} $
$ =-5.42\times {10^{-19}}J $ .
