SATHEE: Atomic Structure Question 242

Atomic Structure Question 242

Question: The four quantum numbers of the outermost orbital of $K$ (atomic no. =19) are

Options:

A) $n = 2,, l = 0,, m = 0,, s = + \frac{1}{2}$

B) $n = 4,, l = 0,, m = 0,, s = + \frac{1}{2}$

C) $n = 3,, l = 1,, m = 1,, s = + \frac{1}{2}$

D) $n = 4,, l = 2,, m = - 1,, s = + \frac{1}{2}$

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Answer:

Correct Answer: B

Solution:

$K_{19} = 1 s^{2},, 2 s^{2}, 2 p^{6},, 3 s^{2}, 3 p^{6},, 4 s^{1}$ for $4 s^{1}$ electrons. $n = 4,, l = 0,, m = 0$ and $s = + \frac{1}{2} .$

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Atomic Structure Question 242

Question: The four quantum numbers of the outermost orbital of K (atomic no. =19) are

Options:

Answer:

Solution:

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Question: The four quantum numbers of the outermost orbital of $K$ (atomic no. =19) are