Atomic Structure Question 186
Question: Uncertainty in position of a minute particle of mass 25 g in space is $ {10^{-5}}^{{}} $ m. The uncertainty in its velocity (in m/s) is
Options:
A) $ 2.1\times {10^{-34}} $
B) $ 0.5\times {10^{-34}} $
C) $ 2.1\times {10^{-28}} $
D) $ 0.5\times {10^{-23}} $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \Delta x.\Delta p=\frac{hv}{4\pi };\Delta x.m.\Delta v=\frac{h}{4\pi } $
$ \Delta v=\frac{h}{4\pi m.\Delta x}=\frac{6.626\times {10^{-34}}}{4\times 3.14\times 25\times {10^{-3}}\times {10^{-5}}} $
$ =2.1\times {10^{-28}}m/s $
