semiconductor-electronics--materials-devices-and-simple-circuits Question 7

Question: Q. 10. In the circuit shown in Figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is

(a) 1.3 V (b) 2.3 V (c) 0 V (d) 0.5 V

[NCERT Exemplar]

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Solution:

Ans. Correct option : (b)

Explanation: In the middle right of the circuit the capacitor behaves like an open circuit for dc0.2 mA current so current will flow from A to B only. Let potential across A and B is V, so by

Kirchhoff’s loop law,

VAB=(5000×0.2×103)+0.3+5000×0.2×103

VAB=1 V+0.3 V+1 V

VAB=2.3 V

? Short Answer Type Questions-I



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