ray-optics-and-optical-instruments Question 47

Question: Q. 7. How is the working of a telescope different from that of a microscope? The focal lengths of the objective and eyepiece of a microscope are 1.25 cm and 5 cm respectively. Find the position of the object relative to the objective lens in order to obtain an angular magnification of 30 in normal adjustment. U] [Delhi I, II, III 2012]

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Solution:

Ans. Working differences :

(i) The objective of a telescope forms the image of a very far off object at, or within, the focus of its eyepiece. The microscope does the same for a small object kept just beyond the focus of its objective.

(ii) The final image formed by a telescope is magnified relative to its size as seen by the unaided eye, while the final image formed by a microscope is magnified relative to its absolute size.

(iii) The objective of a telescope has large focal length and large aperture, while the corresponding for a microscope have very small values.

Given : fo=1.25 cm,fe=5 cm

Angular magnification, m=30

Now,

m=me×mo

In normal adjustment, the angular magnification of an eyepiece

me=dfe=255=5

m0=6

m0=v0u06=v0u0

vo=6uo

Applying lens equation to the objective lens :

1f0=1v01u0 11.25=16u01u0 11.25=166u0 6uo=1.25×7 u0=1.25×76 cm

|uo|=1.46 cm

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