ray-optics-and-optical-instruments Question 22

Question: Q. 3. An object is placed in front of convex lens made of glass. How does the image distance vary if the refractive index of the medium is increased in such a way that still it remains less than the glass?

R [CBSE SQP 2016]

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Solution:

Ans. From the lens maker’s formula, it is clear that n21 decreases then focal length increase.

1f=(n211)(1R11R2)(n21=n2n1)

Here refractive index of the glass with respect to surrounding material decreases. Hence, focal length increases which will also increase the image distance.

[CBSE Marking Scheme 2016]



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